|
A. \(-\frac{1}{8}\) |
| B. \(-\frac{1}{4}\) |
| C. \(\frac{1}{2}\) |
| D. \(\frac{1}{4}\) |
| E. \(\frac{1}{8}\) |
[ 5-8560 - op net sinds 6.4.2025-(E)-9.6.2026 ]
Translation in E N G L I S H
Oplossing - Solution
\(\cos\frac{2\pi}{7}.\cos\frac{4\pi}{7}.\cos\frac{6\pi}{7}\\
=-\cos\frac{2\pi}{7}.\cos\frac{4\pi}{7}.\cos\left(\pi-\frac{6\pi}{7} \right)\\
=-\cos\frac{\pi}{7}.\cos\frac{2\pi}{7}.\cos\frac{4\pi}{7}\\
=-2\sin\frac{\pi}{7}.\cos\frac{\pi}{7}.\cos\frac{2\pi}{7}.\cos\frac{4\pi}{7}.\frac1{2\sin\frac{\pi}{7}}\\
=-\sin\frac{2\pi}{7}.\cos\frac{2\pi}{7}.\cos\frac{4\pi}{7}.\frac1{2\sin\frac{\pi}{7}}\\
=-2\sin\frac{2\pi}{7}.\cos\frac{2\pi}{7}.\cos\frac{4\pi}{7}.\frac1{4\sin\frac{\pi}{7}}\\
=-\sin\frac{4\pi}{7}.\cos\frac{4\pi}{7}.\frac{1}{4\sin\frac{\pi}{7}}\\
=-2\sin\frac{4\pi}{7}.\cos\frac{4\pi}{7}.\frac{1}{8\sin\frac{\pi}{7}}\\
=\sin\frac{8\pi}{7}.\frac{1}{8\sin\frac{\pi}{7}}=-\sin\left(\pi-\frac{8\pi}{7}\right).\frac{1}{8\sin\frac{\pi}{7}}\\
=-\sin\left(-\frac{\pi}{7}\right).\frac{1}{8\sin\frac{\pi}{7}}=\sin\frac{\pi}{7}.\frac{1}{8\sin\frac{\pi}{7}}= ...\\
\)
