1^ste manier :
\(32^{-0,4}=\frac{1}{32^{0,4}}=\frac{1}{32^\frac{4}{10}}=\frac{1}{32^\frac{2}{5}}=\frac{1}{\sqrt[5]{32^2}}=\frac{1}{\left ( \sqrt[5]{32} \right )^2}=\frac{1}{2^2}=\frac14\)
2^de manier :
\(32^{-0,4}=\left ( 2^5 \right )^{-0,4}=2^{5\times (-0,4)}=2^{-2}=\frac{1}{2^2}=\frac14\)