1^ste manier :
\(\large32^{-0,6}=\left ( 2^5 \right )^{-0,6}=2^{5.(-0,6)}=2^{-3}=\frac{1}{2^3}=\cdots\)
2^de manier :
\(\large32^{-0,6}=\frac{1}{32^{0,6}}=\frac{1}{32^\frac{6}{10}}= \frac{1}{32^\frac{3}{5}}=\frac{1}{\sqrt[5]{32^3}}=\frac{1}{\left ( \sqrt[5]{32} \right )^3}=\frac{1}{2^3}= \cdots\)