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\(\large0,25^{-\frac{\pi}{2}}=\)
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A. \(0,5^{\pi}\) |
|---|
| B. \(2^{\pi}\) |
| C. \(-0,5^{\pi}\) |
| D. \(4^{- \frac{2}{\pi}}\) |
| E. \(5^{- \pi}\) |
[ 6-7678 - op net sinds 29.5.15-(E)-28.10.2026 ]
Translation in E N G L I S H
|
\(\large0,25^{-\frac{\pi}{2}}=\)
|
A. \(0,5^{\pi}\) |
|---|
| B. \(2^{\pi}\) |
| C. \(-0,5^{\pi}\) |
| D. \(4^{- \frac{2}{\pi}}\) |
| E. \(5^{- \pi}\) |
Oplossing - Solution
\(\large\text {Gebruik liefst de regel :}\\ \left ( \frac ab \right )^n=\left ( \frac ba \right )^{-n} \\ 0,25^{-\frac{\pi }{2}}=4^\frac{\pi }{^2}=(2^2)^\frac{\pi }{^2}=2^\pi\)
