|
Welk getal is niet gelijk aan de vier overige ?
|
A. \(\boldsymbol{2^{-\,\frac 12} }\) |
|---|
| B. \(\boldsymbol{\frac {1} {\sqrt 2} }\) |
| C. \(\boldsymbol{\sqrt{\frac 12} }\) |
| D. \(\boldsymbol{\frac {\sqrt 2} {2} }\) |
| E. \(\boldsymbol{2^{0,5} }\) |
[ 5-0390 - op net sinds 4.2.13-(E)-28.10.2026 ]
Translation in E N G L I S H
|
Which number is not equal to the other four ?
|
A. \(\boldsymbol{2^{-\,\frac 12} }\) |
|---|
| B. \(\boldsymbol{\frac {1} {\sqrt 2} }\) |
| C. \(\boldsymbol{\sqrt{\frac 12} }\) |
| D. \(\boldsymbol{\frac {\sqrt 2} {2} }\) |
| E. \(\boldsymbol{2^{0,5} }\) |
Oplossing - Solution
\(\large A\mapsto\; 2^{-\frac12}=\frac{1}{2^\frac12}=\frac{1}{\sqrt2}\\B\mapsto\; \frac{1}{\sqrt2}\\C\mapsto\; \sqrt{\frac{1}{2}}=\frac{\sqrt1}{\sqrt2}=\frac{1}{\sqrt2}\\D\mapsto\; \frac{\sqrt2}{2}=\frac{\sqrt2.\sqrt2}{2.\sqrt2}=\frac{2}{2.\sqrt2}=\frac{1}{\sqrt2}\\E\mapsto\; 2^{0,5}=\sqrt2\)
